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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O! f% C: j* B x
2 p# C' D& f) C0 S' W, M发现了一个有趣的现象，/ S: S- q& u y8 e5 s
每一条大路，1 |3 m' ]5 m; y7 U1 c9 ^
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f5 S9 T* k$ u. \' f7 G
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
1 D2 ~, N3 n% h% d2 \; \按4珠路排列，有4种不同的路数
8 k r j! w9 h0 s5 j! F4 N按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
" P/ A6 K) j8 @2 K什么意思呢，可能大家一时不清楚，0 L+ {: M: _7 T" m, H8 |4 `7 Z
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l$ t3 M5 u* o# c; O
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
( `. `% c, N \9 Z4 ]12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
$ a0 W$ v3 l7 i$ |够极端了吧
' x% r/ l1 b+ g/ z按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F4 ]& o8 q& ]! J% O
如果我们去掉第一口，就会出现完全相反的结果：
0 P4 H _$ q% g1 ]0 w$ r2 C21212121212121212121212121212121
# Z; d+ y7 m' w' H+ t变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C2 C2 ~( a7 b' {# J" Q, \( y
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
# ~5 F# U6 e" ^) q7 ~# ^$ }! q所以每一条大路，! R6 V# q$ h. c; z% O6 H( T; s+ T8 N8 ?
按2珠路排列，有2种不同的路数。
3 W/ L5 F! }: n: A4 Y8 ^4 y9 c2 R- \再举一个列子：
3 _4 |4 z/ R7 i- @大路：122122122122122122。。。
" P8 i$ n3 M a- C按三珠路排列：7 }7 n7 h) t% E, U8 z8 D3 W; \
122，122，122，122，122，122。。。
, [3 D. c& [( e6 z2 W4 s3 Y& U去掉第一口，变成：6 G2 V! \" L' c" k: d
5 F. @/ W# M3 N221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
4 ]9 y0 d# r+ ]) F' Q; J去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W4 ^% l6 \& t- c% B, q: X
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
$ ~3 e1 ]# \0 f0 s4 @, t去掉3口，又返回122，122，122，了
9 Y2 e+ y* \" d2 u% N所以每一条大路，
! l# e: { b9 A6 d按3珠路排列，有3种不同的路数。
4 T+ y3 T& {) _$ _) B u* A! L同理：按N珠路排列，有N种不同的路数。
1 D7 W5 U" Y5 j: Z4 P我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
' M$ X6 U, Y4 j s6 x( W% `6 J6 d% L字串83 L: R) G1 V- s2 Y+ Y
# x; I6 x9 P: g( d. b# q- p, d3 [6 U. s5 J' [0 {1 A" m' k( @ Z5 R5 k f7 B: H! D2 z
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |8 }: h& @1 l: I0 N+ w; s3 k
2、为三多理论提供了下注的多面性奠定基础。- w9 ^- q7 S, B, ?; Q/ T
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.; ~: d& t( g* h0 C
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