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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O" Y, [' T9 M5 m; H* T& B
% v! c! [5 \- F% j4 F
发现了一个有趣的现象,
0 P' T. \" W+ M每一条大路,# w8 g) l( g/ J! Z; L: ]
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f3 Q5 y& ]1 |( {- L
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z/ X+ j$ ^ j/ M0 n ^
按4珠路排列,有4种不同的路数
: H- u6 h9 x0 r7 Y/ W按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C" ~2 w, t8 M/ N6 l
什么意思呢,可能大家一时不清楚,7 o: E# [; ]% c0 Q
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l1 i; f( A9 T5 U! [$ I. z5 M2 Z0 e
假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u
; P, p: o' ]$ E8 F4 o5 p12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h2 a- k9 G8 }: J) y
够极端了吧
' {' l" [% Q- a8 t2 b& i- \ l/ T" q按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
! k- @' B+ B q4 {2 e. Z如果我们去掉第一口,就会出现完全相反的结果:
* [( F q+ u7 P! c3 J& w3 h21212121212121212121212121212121: e( r" v4 J/ ^: K
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C+ D z6 s; a2 ?: d: x6 k& q
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O/ N( F1 J3 [# a; X- A# }, x
所以每一条大路,! R6 V# q$ h. c; z% O* N" w& p8 ^( ^/ p
按2珠路排列,有2种不同的路数。
3 F6 k; G( d0 V6 y/ ?再举一个列子:! _0 H. K J/ S3 ^* V! C9 D( L
大路:122122122122122122。。。
/ [* h3 V* [" l: e7 Z# z( q5 n按三珠路排列:9 y- o+ o! f5 N) E3 W4 t
122,122,122,122,122,122。。。
# K A6 a; P$ u去掉第一口,变成:6 G2 V! \" L' c" k: d
$ q Q& a q" ]% s3 N0 h221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M+ |( x' ~* c( d2 L5 o0 h
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
1 y$ f' U/ S$ m7 u# S3 a( U3 B1 |* ]: e212,212,212,212,212,: y& l, B; I6 e- m. J# c) `0 E( d% D) z' w1 N' g; S& d
去掉3口,又返回122,122,122,了
& @( x) c6 m9 S- F4 q- g* T. S% _1 S所以每一条大路,) s! N0 o' H" s E3 P
按3珠路排列,有3种不同的路数。
' z& D$ T6 [' `" I2 M& i. a同理:按N珠路排列,有N种不同的路数。
9 @# x1 L) P j$ H) |. t% z. |我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
( C6 y T3 z% s9 T( N) h字串83 L: R) G1 V- s2 Y+ Y# m' M; j4 W" y) w/ K7 n* p
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @# W/ P" S5 A3 K
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |! h- K0 u0 S8 x
2、为三多理论提供了下注的多面性奠定基础。1 `# ]. {& v$ N% p9 j
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.; C \9 X& ?% e0 P% A; u: S
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