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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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$ h# M% [( M: k( {' \4 K 假设大路开这样的路:
8 Y" [2 f: q# @4 O
/ u! ?! \ W- S. ~ 12121212121212121212121212121212。/ U$ ~, _" t0 @
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按2珠路,就是BPBPBPBPBP。6 q0 ` C M5 f+ P; R
( ~2 b" c. a- j. P7 c) z* z 如果我们去掉第一口,就会出现完全相反的结果:/ m. e6 c# s. t) b" c
8 m7 V3 X# m1 F$ R. ]8 R 21212121212121212121212121212121。+ M# u' I# p- U' c/ E* H) a
: d% A8 O5 q, e4 u/ k4 E 变成了PBPBPBPBPB。& p/ c3 }' I& _# i _
- s0 A3 V6 l4 Z0 G9 t 如果我们再去掉一口,又返回第一种情况了。
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所以每一条大路,按2珠路排列,有2种不同的路数。
3 q8 b \/ [- p/ a" @7 h P
8 F0 q3 O; N% T8 x 再举一个列子:9 R/ J( }% ?, j
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大路:122122122122122122。
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) \# v0 y1 m, j8 R! \) P 按三珠路排列:4 p( [' Z' r$ a; V3 D
" T" v2 V8 k! f4 T6 x, k
122,122,122,122,122,122。
: }1 T t$ k& S
" S9 ]! w) K3 N" y/ `- m( o 去掉第一口,变成:
! P8 P4 J# g: i: v; E- R
5 u- w7 s% ~: b5 x5 T/ M/ D; h 221,221,221,221,221,去掉前2口,变成:
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; H& j! f: c4 `" e2 {6 f 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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6 y. g! O8 p, v, b- O 同理:按N珠路排列,有N种不同的路数。0 i3 z- N* V1 K
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我提出这个的意义在于:
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6 m) m, }% ]/ u' _ 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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% T" t0 ?( Y% o6 s* g+ Z 2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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