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9 y% q0 x) w- [, h, R0 `: k通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。* J. O! n% T6 P2 a3 X
2 j6 K/ R4 s' E7 ~ 假设大路开这样的路:* ]6 N( ?7 n9 q; g' Y
" P9 z! c- o% _4 U8 s7 b
12121212121212121212121212121212。
$ s3 V0 [" t% W/ z% B6 V& g' Z* H6 P% G
按2珠路,就是BPBPBPBPBP。! c- S8 |3 [/ ~
$ H4 I' B/ I6 P* r) \# R- t 如果我们去掉第一口,就会出现完全相反的结果:
5 w; A3 s' F& }; m3 o6 x: x5 I# q. W2 |$ E; Q4 W! b3 b
21212121212121212121212121212121。2 l' r: g5 b; p% W% e# J
) j$ ]& x% ? b3 {' Z _3 j
变成了PBPBPBPBPB。
+ U' t! U4 |; w" W. E3 ~3 G x/ ]& k2 O
5 V1 S) m4 x& z! A0 }3 j 如果我们再去掉一口,又返回第一种情况了。
. [: `/ o" \4 O) W4 k. p7 F7 v& \6 z5 y$ p* S2 w
所以每一条大路,按2珠路排列,有2种不同的路数。
+ f2 g* \ g6 s1 v/ W9 @% g8 J1 ^/ T, t- ~
再举一个列子:6 r: p! E1 U4 \
6 S2 m, h6 Q$ M F2 V) a- I
大路:122122122122122122。
' g4 j0 B; E! B! q
* g5 R# {" ^ N j/ Z5 s 按三珠路排列:
) u# i1 W% m; W1 [0 Z5 d. C- H/ x2 P) Y: U
122,122,122,122,122,122。
( c V" V( j6 O/ d+ ]" T) n5 D
8 Y, z: q7 s$ j0 F5 G 去掉第一口,变成:
' v, l2 E, W6 ~0 U, M8 t/ V" {
: D* G) I7 N1 P 221,221,221,221,221,去掉前2口,变成:
7 D, M9 C; V' Y, X) s, @, W1 h
, g q4 j1 z7 b5 m+ v3 S 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
' q8 q( y# d! ]3 l Y3 w% [
/ F0 ?8 K) c8 o) W 同理:按N珠路排列,有N种不同的路数。7 w) l% V$ F* s0 v+ {
' E) P, ~! q* F2 P
我提出这个的意义在于:
* \5 b5 p' B% T; a4 ~1 G
; R& y7 n- `8 ^# t" {+ v 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。3 N) p2 o5 @( V
0 u, }( y2 }2 H" g: \$ ^
2、为三多理论提供了下注的多面性奠定基础。
x& Z+ H) E1 } p0 N2 I6 t9 r* g( Z4 H; a5 C
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。" r$ ]: f" m4 u7 w
$ O. U* F* y+ p3 B) h* p' G/ M. Z9 @! n& i9 T) A; Q y
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