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[lastpost] => 2763770 【YZ】9月8日投注流水7204元 1757399631 rainwang
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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+ P; R: h- a* d; I% ^$ R6 j+ W& s" ` 假设大路开这样的路:7 {' G% T ]6 J' n* h
$ M& X' a/ j4 N- x 12121212121212121212121212121212。
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+ _3 g' Q8 M* ]2 R) a 按2珠路,就是BPBPBPBPBP。& L. p; t1 J: `+ j3 N
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如果我们去掉第一口,就会出现完全相反的结果: v" N7 ~9 J! k7 w1 |
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21212121212121212121212121212121。
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变成了PBPBPBPBPB。
6 a# x9 S2 d+ R& O5 k. Z
4 q2 \6 K1 I7 t8 R8 ] 如果我们再去掉一口,又返回第一种情况了。9 ^, X/ C: q2 N0 a/ L: N
# i; d& i$ v" A2 |" V; n1 A4 L! d 所以每一条大路,按2珠路排列,有2种不同的路数。
* Q Y8 s [! z+ i8 Y7 N0 J/ _4 S6 b3 U0 [: S7 C' l+ J) Q
再举一个列子:
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大路:122122122122122122。8 a, \0 E& s# G6 M
4 u. i& `" c. U+ r) k% W
按三珠路排列:
0 W+ f D3 Z. b+ i* k2 Q I: z8 K5 }5 a9 U
122,122,122,122,122,122。
% g" s% p2 F7 L/ y9 r# l" i- b& w' G% Z4 Z
去掉第一口,变成:
: g1 a, w s' l- K0 X
$ K' |1 n: d9 @6 Y) B/ ~3 r 221,221,221,221,221,去掉前2口,变成:
% Q% U2 b) U- N! r& K, U4 `+ Y5 d: C' H, T& @: R/ d
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
: j: b0 b/ J/ o& u* c& a' |; o5 k R
' V$ u* ^+ D1 y3 [ 同理:按N珠路排列,有N种不同的路数。8 c# ^! n& [5 }/ j. q% a" P; x
0 [& ?3 ]+ S/ F8 o p 我提出这个的意义在于:; z5 c+ ^) t: o( b2 V" R6 N4 i
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。* X; V* J7 P* z$ v- o8 P7 V
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2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。: p7 C" S; c, V4 o
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