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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。 E6 G d4 U1 D+ U" `
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一般来说,
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二连赢的概率是25%
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三连赢的概率是12.5%0 M& D& j5 b m5 H7 x- R
7 E. |0 m+ f# u! N* y四连赢的概率是6.25%6 y* ]0 r. P1 M
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……
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4 U8 o' U+ b7 e+ t) V( d; t$ e/ k3 s; R十连赢的概率是0.09765625%9 s- s/ \1 w( u; [
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
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8 q6 l" S6 \' O- U% t3 M* |百家乐的真实概率含义是:* t! P/ Y7 F3 M P2 C
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球8 G: v. j3 f% \( p, x! F
' G% y. K0 z; k1 a; K1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。! ]- h5 z1 z# B. l8 [8 C
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你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
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& r' ^! D9 W0 W; k! h) D1 M: i你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。* S9 e* ?" P. w& b
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另外一个说法是,' O/ r4 ^6 E- [, Z- U
7 z( y7 ~0 C7 n4 |! b' I/ d0 v ]1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。' F" V. z+ G! }5 V8 ~2 i( y% S
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。/ }' y: J" _; n5 I
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。) ]* p c' z- \9 m& @* i
+ c) ^4 v% k' G0 g平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。: C+ n6 v; o2 u) F
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。- v: {9 J/ q2 e
& e4 K* e4 J' z; t$ [" W第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化2 Q# U) i) }4 t# C
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第三,凯利公式的问题在于:形而上学。7 f* v% j4 ^' t% P% z
5 Q5 Q6 w$ R2 w1 Q- Y) j W首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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事实上,你玩的时候,基本上每次都能打到。
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/ C! `& K9 D1 F1 R+ U& \6 F; H因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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