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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
+ [* l- o& x+ M7 U: H& r
* O, B) I8 Q, {5 F发现了一个有趣的现象，# I7 y F9 U6 e# ]. F
每一条大路，
$ \3 k8 i& [- \! z按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
: [$ `6 \( R/ d" N. g t6 H按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z0 u7 t4 G9 |6 N" Q
按4珠路排列，有4种不同的路数. ` q$ O. L; x0 W Z1 D
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
: R; L" Y3 r8 k, B什么意思呢，可能大家一时不清楚，
( ?/ m l( ?/ G2 E1 P& g. r我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l, B8 a' ]7 l8 |2 C# n3 E9 \: ?9 J
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
" N& u8 M( S0 R* R( e7 V- o0 I) f4 n* m12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h( j$ L4 l& A7 g
够极端了吧
4 `. f. o. h) w" C5 r7 O按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F6 B1 X" n9 W4 K* m% G7 E, v
如果我们去掉第一口，就会出现完全相反的结果：
# V4 K4 C* c+ \) E" W. G! [1 n212121212121212121212121212121213 ?# ^) A6 }4 T. g
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C8 F) n+ \3 A# ?5 T( z! i; f+ J
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O0 v1 R& ~# J- ~, |- ]
所以每一条大路，! R6 V# q$ h. c; z% O; e. w- Q+ @' T* Q2 F7 n; `
按2珠路排列，有2种不同的路数。8 ~7 F4 |9 P2 U4 u( R% g7 i1 E, s% I
再举一个列子：$ J1 B+ K( n$ j4 f6 l
大路：122122122122122122。。。6 N$ r% {9 v* G) D' S: [
按三珠路排列：0 W/ G& @/ \# E( U6 \
122，122，122，122，122，122。。。1 d6 k; y7 i' m
去掉第一口，变成：6 G2 V! \" L' c" k: d
0 y8 b% z1 [0 t" E4 M221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M$ `( u, i/ P) C6 h7 x$ {% N6 T
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W% W% T# V8 F0 E7 c. J5 f" A
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
2 v) I3 b9 m, I4 {- s8 f去掉3口，又返回122，122，122，了% H5 y. H: y6 ~; e+ @4 J
所以每一条大路，
9 X$ k3 R x: Z6 Z% ?按3珠路排列，有3种不同的路数。
4 C1 p7 z4 Z* T同理：按N珠路排列，有N种不同的路数。! r2 c2 e N+ N! b
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O0 U$ `9 M% b$ i' p) l2 y- _
字串83 L: R) G1 V- s2 Y+ Y
2 B& L8 m M4 b+ v! X4 _8 j- p, d3 [6 U. s5 J' [0 {1 A" m' k( @5 R4 x' B4 g/ x: y/ d8 [+ I1 i- w
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |! K5 Q! ?7 w) q$ \+ k) H; u$ ^
2、为三多理论提供了下注的多面性奠定基础。4 v0 x. I4 H& U5 c8 g6 x( O
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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