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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
& z% A1 Q8 B1 j7 e& q; [" r4 s* x5 s1 t1 U% [
发现了一个有趣的现象，
3 U+ H6 I i& Z* f* E+ L7 S每一条大路，2 {3 Y, ~+ Y6 T% h0 R1 x
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
/ ^+ S% I/ Y# M6 {/ G9 M3 x按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z2 D/ {6 { e/ n
按4珠路排列，有4种不同的路数
6 N4 G$ f! y: L* k按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
* a( m, F8 m- g9 }( c! d什么意思呢，可能大家一时不清楚，
9 P% q' C# N+ k" @2 v我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
) P1 ~8 w% W( q. d1 C: R, m假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u6 r+ ^7 U6 [1 W0 q) M0 n- W
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h& q: a6 z4 D2 p4 L- J6 u
够极端了吧
! o. t6 ^& ]1 U4 M按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
% b1 N/ u: n8 Q$ W- ^' e3 n如果我们去掉第一口，就会出现完全相反的结果：, Y6 y! Q1 W! X0 W) J f( k3 E" d
21212121212121212121212121212121) D& T; A+ M- S2 Z+ I. z) A
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C: l6 N7 H3 a. I5 L1 E8 w3 ]$ t
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O$ R- s% ^& \5 E. i6 u* N# Y3 a+ |, l
所以每一条大路，! R6 V# q$ h. c; z% O/ {3 Z7 P3 g+ F
按2珠路排列，有2种不同的路数。6 i! N4 `2 e1 a" o! a2 {4 L
再举一个列子：! Y, x% L: q, s! H& S) P+ O
大路：122122122122122122。。。
* J! |5 X' X. B1 x' U" z按三珠路排列：
& ^2 B7 i8 ?3 l1 q122，122，122，122，122，122。。。; p& N# A# x8 a/ Z' y
去掉第一口，变成：6 G2 V! \" L' c" k: d9 M1 y0 z- X' g7 @
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M R. _) i. B/ x4 L& X# J2 i
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W2 q; Y0 g' G2 Z$ @6 u+ E8 _+ f
212，212，212，212，212，: y& l, B; I6 e- m. J# c) ` A5 \; P; J9 k7 m! A$ n' Y
去掉3口，又返回122，122，122，了
8 G4 x6 J$ w @/ s+ J; B: ~* h所以每一条大路，
5 }9 J7 R! ?! A8 v' o* P按3珠路排列，有3种不同的路数。
4 d. t9 N2 H+ j同理：按N珠路排列，有N种不同的路数。
& h, G& `7 V# R7 U7 X& x5 ?: {# ^我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
0 L) c4 v j# F: A, U+ _* }字串83 L: R) G1 V- s2 Y+ Y$ o! ^/ U4 c- v; y4 K! o" z
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
3 ^( Q, L5 j9 @3 M3 _# I+ L/ ~1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |$ [, @4 f, H7 i0 P
2、为三多理论提供了下注的多面性奠定基础。
. f1 \4 z8 b. S2 Q3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.! e, ]$ m v. N: G Z$ e h. R
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