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[打法交流] 百家乐珠路理论技巧(转)
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通过我几个月来对珠路理论的研究,5 R+ y* d$ ?  k6 I7 G/ O
1 z* v& S0 C  \1 t4 ^- e  i9 w  G5 L) o. ~- u# p
发现了一个有趣的现象,
' v) G5 X: x& Y% ]; \& A) F每一条大路,
# J. Y! {7 Z. m$ K1 s- X3 x按2珠路排列,有2种不同的路数1 _% l2 j  Y8 @" u) {# f* L# \- u' n2 l/ \6 ?% z
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
8 T0 b4 O  B; R7 o9 Y" O" `按4珠路排列,有4种不同的路数8 ^% @9 m. Z5 V
按N珠路排列,有N种不同的路数。: n1 f3 R9 @  p% ]* C
. }( U( {. p# w! r/ j7 t什么意思呢,可能大家一时不清楚,
4 X8 Y; k: L8 ^# E# }/ h$ Z# i我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
8 S9 Q, g8 _/ s1 E6 |假设大路开这样的路:! z  ~0 G3 v. K' o5 A4 ]" }5 w# u$ k9 D! x. U5 e7 R9 `5 k' v
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h4 f0 L' y8 o1 G+ U
够极端了吧2 t2 p& o8 y0 M7 j
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
2 y8 S5 L8 {" M1 O8 i如果我们去掉第一口,就会出现完全相反的结果:5 j/ W: @( r) |1 ^3 Y
21212121212121212121212121212121
- F+ I. P" |. f变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
, x4 m  y& u, v, L, q% [- C) y如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O( J. g0 X6 X7 j! C
所以每一条大路,! R6 V# q$ h. c; z% O
2 k) G) ?( o( C! j- J按2珠路排列,有2种不同的路数。0 j0 ?# b3 I, G8 k2 f, g3 h
再举一个列子:
/ v/ x' M' N. ^9 b- f大路:122122122122122122。。。  d( i3 K8 }  n9 t
按三珠路排列:* H8 Y& h$ T3 N, ^# z5 v' v
122,122,122,122,122,122。。。
) X" t0 F: h  R去掉第一口,变成:6 G2 V! \" L' c" k: d
# _+ r) b; E- r+ i221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M9 A+ B/ C7 `2 |- ?9 H9 a
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W  a" t7 t2 I/ `, t) s( y
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `
! [2 Q8 ]$ B5 `去掉3口,又返回122,122,122,了
; I( G& K; p3 H) H% D所以每一条大路,& x5 R' o) R7 x: V1 }' v
按3珠路排列,有3种不同的路数。% y0 Q! {0 O! ?1 Y7 V
同理:按N珠路排列,有N种不同的路数。* y6 s- ~8 W5 h0 Q4 s" @2 P. S( h
我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
5 _, w: e' l: V6 Q' i' R, z' }# h字串83 L: R) G1 V- s2 Y+ Y
9 H' I+ K5 Q7 G4 r- `5 w/ c: ?4 n- p, d3 [6 U. s5 J' [0 {1 A" m' k( @/ r7 z0 g! x) p% t# P; c
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |9 @: s, v2 S: g
2、为三多理论提供了下注的多面性奠定基础。
1 n# f; z( B; v+ N) ?& W3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.! Y) ~, @+ t0 w  C

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