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+ m! @" v% D1 y1 x9 a" s/ Z
. v2 O4 F. `' O1 j9 y( t+ |% W通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
6 z% ]0 H9 i5 r7 ~5 j2 c7 {0 D# Y4 l X
假设大路开这样的路:
; r/ A& X: T n+ w; e) i7 u7 ~# y% u% d0 M# C: s6 L1 y
12121212121212121212121212121212。
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按2珠路,就是BPBPBPBPBP。
/ G+ K1 E( F0 P, J" j- n# M: Y* m) ?2 \7 `/ a" x
如果我们去掉第一口,就会出现完全相反的结果:
% O% V1 C5 y" w3 [+ M/ b- |3 H* l. |1 N1 \+ L Y
21212121212121212121212121212121。3 y) F/ ]+ p1 L3 P, f* K
6 ~& ?) {' x0 h 变成了PBPBPBPBPB。
2 G: ? c8 l2 q5 N6 p
6 _- B; q; j6 w7 S' \ 如果我们再去掉一口,又返回第一种情况了。, f$ [1 j: l- S) l0 V% {- S
% V2 a; T' s! w& C4 W. u/ x 所以每一条大路,按2珠路排列,有2种不同的路数。
& P0 s6 X8 V. w% Y5 j8 c" [& ]
: | ?. _" x$ P+ R 再举一个列子:. I, G) Q) p, I2 q4 H
9 m Y1 E; Y3 v/ B- o: T9 V
大路:122122122122122122。
0 q% d( T, M M0 m. g
. I# y# I# P' O) d& v 按三珠路排列:
, w% @4 \6 L+ {9 Q& x0 h5 {
9 t4 h- M, q1 |) ] 122,122,122,122,122,122。
- v1 {( }; g! C! }) Z C; O! G S3 T+ {% i. g
去掉第一口,变成:9 C9 G' d* o* N! r( q
' T+ S* c* u/ m$ e 221,221,221,221,221,去掉前2口,变成:
$ E" m+ _( f& J. {
* O& d4 G4 d. \$ D 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。3 ?7 r0 r% l# @
8 f/ }/ i: L" u8 l3 C
同理:按N珠路排列,有N种不同的路数。
6 |% F/ g$ c$ |% w: ~! q9 b) F4 Y, S- ?' ?$ f# b4 X3 D0 G
我提出这个的意义在于:# f4 ~7 C! a" k8 ^8 k2 h3 n! R
V/ G$ [) |" M9 E' L
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 p+ i3 r' a6 v' k
5 \1 o( V! l: K5 C! I' U 2、为三多理论提供了下注的多面性奠定基础。) L1 p4 P9 Q$ g( N9 D2 Z3 T
( u% k6 P0 Q3 E8 c, i+ J 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。6 r/ x% }/ r) K: s* a& C7 B
4 P- ]7 E# n z5 A" T
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