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[打法交流] 百家乐连赢概率和连赢策略
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1#
很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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一般来说,
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二连赢的概率是25%5 a4 n% D' X9 C" D, N* {5 r; V
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三连赢的概率是12.5%7 a7 m) L# R* ^+ r

4 S  U1 \6 f" C四连赢的概率是6.25%
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; ?9 ^" t$ ?7 u1 H……
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( f8 t$ Q, X0 d* D/ Z/ D十连赢的概率是0.09765625%, S! Z, N- y5 Q5 l3 \
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。# |1 a, t0 j+ D4 G7 ]
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百家乐的真实概率含义是:
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) F: Z, [% b) R: a$ z! i7 m0 ]8 w假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。; W* u5 q, Y( s" u3 t$ A

+ {  e7 M( }1 F/ w你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。5 T' Z, e, c; x' ^4 l/ o) U
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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另外一个说法是,
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1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。! |) d5 [3 ?$ l5 }
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。3 Z+ z: P  J& S, j: d5 `
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。
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* I! {  d; b, M( k+ f4 n对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。; |( x4 B4 C: l5 O- w

' J+ P3 e$ n8 o% |. y$ D' z0 e举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。) E6 O* W; E' n& E# _+ T; `
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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, k1 j" o: p3 d) z# O0 ^第三,凯利公式的问题在于:形而上学。! ~% _4 O0 {7 p+ Q. F* y" c
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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) c  ~7 e- j" y, p4 U事实上,你玩的时候,基本上每次都能打到。
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& g3 }/ m6 o* b! o* _因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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这个概率还是需要运气加成的
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看来,只有跟随运气才有一线生机呀
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4#
不管是概率还是策略都值得了解
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主题回复处广告图案-天策传媒
又找了方法,不只一个吧
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6#
百家乐的玩法也是来学习下了解下啦。
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