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* k+ n N% Y/ F+ s5 h8 A
8 [6 J$ o& V9 V Y- L0 y; ]通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。- f& |. _+ J1 J! y8 K! T" d
0 ~! E$ P. {8 }( X 假设大路开这样的路:. }7 j0 \4 @, w+ C
1 f0 w. e: l$ @1 X7 c2 S! |$ {7 P: q0 ` 12121212121212121212121212121212。/ ?3 {/ E; l- m; _6 a- U
& R4 ~, t6 e ~# ~4 S
按2珠路,就是BPBPBPBPBP。 C" l; Y4 r+ E4 ~% i5 n- @, a
0 J# q& p8 P( y8 H 如果我们去掉第一口,就会出现完全相反的结果:; B' e) T. G9 N
! W9 Q8 ]! A( e- j. c7 U 21212121212121212121212121212121。
9 }% x& F$ c. z1 l) y) k0 M
. r( q& K" H- v 变成了PBPBPBPBPB。. ~7 g9 R& g8 l ~
8 H( o! {7 Y6 {2 v7 h
如果我们再去掉一口,又返回第一种情况了。/ I* }$ x/ t% \$ H5 R/ Y
8 `* J& g* X4 p- Z# w0 i
所以每一条大路,按2珠路排列,有2种不同的路数。
5 ^! p5 O6 w- J
) y( H, I3 a+ B9 z S 再举一个列子:
" g# _$ Y, P/ w
; _3 y" N" x- a 大路:122122122122122122。
8 y0 F$ B7 C% l+ r3 R& [ _1 k6 G' ]0 |7 x$ V
按三珠路排列:
# m5 u3 I7 _5 k+ q: Z' D2 K; t* x# q' k8 O: g7 r' w) H) T
122,122,122,122,122,122。
1 x1 N; H R; M( O6 [- @# o! ~; k$ ], _
去掉第一口,变成:
% x# X$ |; @0 w9 t' g
* j( h* C6 J; o' h# w 221,221,221,221,221,去掉前2口,变成:7 M& x; f0 W, x* Y- `6 R
6 {% x- l- v% b9 r8 q
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
, p) o& t, _" J$ |& L; @! |4 u9 ]: M& \
同理:按N珠路排列,有N种不同的路数。
+ C1 f6 J& R* o8 r: r1 }: w
* x! v5 ^8 y" X) \5 \" J 我提出这个的意义在于:
5 } [- `5 \" `' ~ z& S4 I& a* G
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。. L# R) o/ r' Z& J9 r+ S+ g
% l3 T4 y7 Q" h% _3 S
2、为三多理论提供了下注的多面性奠定基础。
3 N' r! k6 W l" f! G/ D
. q: t9 t7 q; r9 P% o; @' |* P 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
5 M+ r7 f4 u9 \% ?& h8 e! i' E4 R! g, z. _4 D" X
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