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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O7 Y9 W0 I9 ^/ L+ E. d
! C% q2 B1 p" g0 m
发现了一个有趣的现象,
' g6 S! x3 M+ \2 j# `$ r6 T2 h* t每一条大路,
' g, T/ ?7 {/ _按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f/ j* s# r0 @3 L. r/ C; d% X0 C
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z3 V% r4 f/ W/ h' W
按4珠路排列,有4种不同的路数
% g9 a. u5 l- ]+ u! X/ d按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C* r4 n% ]9 w, [
什么意思呢,可能大家一时不清楚,$ y; w; I# U4 V' n0 x6 v; X( n
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l8 S# b8 F! ]" e
假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u. o+ K+ t9 I0 P* |3 A# J. q
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
" q+ R, P" e4 P够极端了吧
0 p& Y+ i5 m, n( U按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F" j- m& {. }& F+ e: |
如果我们去掉第一口,就会出现完全相反的结果:
5 H# [ m M; j/ f s5 R, U6 i2 d# ^21212121212121212121212121212121
9 Y3 }$ \2 l0 z' z/ m% `变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C$ w1 X% A" x) ]/ }/ H# t
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O% R7 d/ z6 B; m" y$ r8 V1 T
所以每一条大路,! R6 V# q$ h. c; z% O
& K% D/ c, d% K) k按2珠路排列,有2种不同的路数。6 \1 H* n) J8 Y) `1 v4 B+ p
再举一个列子:
/ b. D3 a' b0 b9 G* b大路:122122122122122122。。。
1 J) e% X# ?, m0 ?$ h按三珠路排列:: @! B2 }/ ~( R, D
122,122,122,122,122,122。。。; K9 B+ n8 O( y, Y( `# k
去掉第一口,变成:6 G2 V! \" L' c" k: d+ q q$ m) ^+ |. N: C$ E0 k
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M, C) S3 i1 J% \& T. C& } T
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
& H( ~+ q; e* P# k2 N212,212,212,212,212,: y& l, B; I6 e- m. J# c) `
+ O1 i) O6 X; k3 X9 f7 ~/ m, o* |去掉3口,又返回122,122,122,了& d! u6 R% m, |) [
所以每一条大路,% Y3 A8 }# a4 `1 D% k" I
按3珠路排列,有3种不同的路数。
- F6 @$ H( Y: l( p5 |同理:按N珠路排列,有N种不同的路数。+ y: X# c0 y1 S: c- b: v: u6 @' b
我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O( V* @ c% p1 Z) F- T9 k- y! j
字串83 L: R) G1 V- s2 Y+ Y, h, h2 c6 P' Q, w& O7 X
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
2 M- _; f9 ]$ g# U1 z; O5 p1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
0 s2 r2 f- X+ x9 x; u- G2、为三多理论提供了下注的多面性奠定基础。
9 Q3 b4 t- o5 U3 K# \3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路." v5 ?5 A$ K' @4 l8 p9 O. f' E+ b
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