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4 ^/ s" y2 n4 C7 e- F* j- C
# E3 r6 X% I, w) q. `5 M通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。% W- x! r7 t3 w7 H4 ^
% a9 ?" R1 F* S+ e9 ]2 U 假设大路开这样的路:
4 N, g- M M% s0 o& r0 C& i ^
1 t7 G1 c6 n( M* l" O. r 12121212121212121212121212121212。' H% i; [( n( W' n6 E' d- f
/ e" [; a1 O, O9 R, d 按2珠路,就是BPBPBPBPBP。
9 u/ H2 m! w+ P, M' Z3 V$ B
; G z& M% y* C8 l2 X; w$ G 如果我们去掉第一口,就会出现完全相反的结果:
- F0 q2 \* z% h, y- u' M0 c8 V0 A' Z4 p$ u5 k
21212121212121212121212121212121。
@0 D9 s# l* {. Y& e. N
4 o+ r9 q# J: O# J, L: l" l/ ~ 变成了PBPBPBPBPB。1 z1 g) W/ r1 s9 l2 I! J
- v7 t" w+ ^1 h$ z5 V
如果我们再去掉一口,又返回第一种情况了。7 u' u% S8 D- w6 T' v q
) C! Z: P' p. C& G) X. v# |: b
所以每一条大路,按2珠路排列,有2种不同的路数。% P, v* K3 @0 J" A8 w9 H
. N' u0 d7 A0 _0 v
再举一个列子:5 Q' i! D3 n) P. Q( Y; u
, s3 b! ?7 o5 x. e) c8 E) n, g7 k& _ 大路:122122122122122122。5 \5 C* K% ]) l. J7 X0 F
. N( Q' q1 c3 q0 U: Q5 M
按三珠路排列:* i4 U4 S: @4 z! v" ]+ y6 ?3 M0 U0 V
" G) N, n" x3 X3 M7 L 122,122,122,122,122,122。
# N; r2 q* @# [) G7 o
7 D7 N; }. E! w) A; [0 S% @; f 去掉第一口,变成:
1 e6 K2 r) O( N; w7 D
6 Q1 ~0 {2 S/ G3 ~+ r$ {7 \ 221,221,221,221,221,去掉前2口,变成:
% l0 ]- k @: o- T1 w( o
( z8 U% w/ q+ J1 h6 u$ y 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。$ Q6 \, U4 K+ p4 P5 h$ f" X& M% N1 @
) x- x |0 P/ O8 N" I 同理:按N珠路排列,有N种不同的路数。7 f; d* j) B7 m" q- n
3 c, B; i$ G$ t; M5 M4 U( R 我提出这个的意义在于:
# j7 A% }! r# F3 f$ G2 ]& q# `& E( T3 C" q( v D
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
5 \* J3 g6 S- I& e4 l/ Q0 S3 ]6 c( x. x* `1 d8 E
2、为三多理论提供了下注的多面性奠定基础。
3 h1 L/ O3 j2 h5 t' {' U
7 m4 `: t( P% A9 |- C 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。/ n% ~+ Q7 j) ?6 u' A
% x6 z8 X; K& I/ w* N9 i7 d& [4 p. `6 |8 _
, M$ X- `; H0 I7 Z8 N
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