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- g) b/ m7 U u* S5 `- P( e通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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假设大路开这样的路:# R. Q# \5 W" X6 O
# @: F+ \, B' x/ F. @8 g3 u
12121212121212121212121212121212。
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' P$ A; F. x" E% `1 e2 z7 w 按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:
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! z& x) m2 j) o0 S 21212121212121212121212121212121。" Z% \ Y [. h0 F( r
5 v* L; G2 Q. k8 ~0 u) ~ 变成了PBPBPBPBPB。9 A- e( F0 c6 |- e) ?: z
( y4 B3 e5 L: c& D 如果我们再去掉一口,又返回第一种情况了。
6 C! S% l& W6 f9 i3 c* c. G+ v. G0 X& `) q# j6 h4 p1 r4 E
所以每一条大路,按2珠路排列,有2种不同的路数。
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1 B3 J- L: v2 `, I/ ~' d+ D4 V8 a 再举一个列子:
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大路:122122122122122122。; b- Z$ |% h/ g9 I2 y
6 p% A8 j* ]3 {; d: R% S2 U
按三珠路排列:
& O0 S# C0 F7 Y! R, J7 w- Y U/ V1 M. ~9 f7 }( b- w0 B% R8 _6 @
122,122,122,122,122,122。1 c( v& w. |$ K. t/ o" s8 L' Q
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去掉第一口,变成:5 ~' V- I5 {; S2 o, e0 N
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221,221,221,221,221,去掉前2口,变成: X) ~# O/ V% g- K; c0 m* }2 j) ~
" m2 z. \/ G6 K' P* \$ A 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。. l) d7 a [$ Z, p
/ u3 t, a6 b9 Y$ T3 x
同理:按N珠路排列,有N种不同的路数。
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" L* n& `/ I5 _ 我提出这个的意义在于:
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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3 o9 G2 E( M2 k1 |' C 2、为三多理论提供了下注的多面性奠定基础。
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F! j5 F% N& U 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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