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通过我几个月来对珠路理论的研究,3 o$ z4 n, P- V
; _2 ^; |" x/ b+ L, Q发现了一个有趣的现象, p: d$ b) r8 y7 p4 {
每一条大路,
7 W' B9 Y! F P( U7 d* d按2珠路排列,有2种不同的路数
( M9 d5 V, g: J6 C" _0 U. B3 ]8 I按3主路排列,有3种不同的路数% w) u# l. b0 H, S3 J
按4珠路排列,有4种不同的路数
6 i4 w& V0 |. P2 P- |按N珠路排列,有N种不同的路数。
- a. v: P& @, K# h ~什么意思呢,可能大家一时不清楚,
/ h- f7 q3 R* U, ^5 t* L/ y我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。) f' `8 _. `# x2 q6 p+ C/ @% @! C+ b
假设大路开这样的路:& a# r. r1 k5 N
12121212121212121212121212121212
4 q' F7 T0 |" Z+ b够极端了吧
2 p' F( M) z; P7 \! y按2珠路,就是BPBPBPBPBP.....
3 l2 V$ H- P# }& L, P0 [如果我们去掉第一口,就会出现完全相反的结果:5 Q: R- L; z' u
21212121212121212121212121212121
# H! g$ z1 d) M0 b! O. W) E变成了PBPBPBPBPB.......3 X% J7 \0 V& k8 f4 b" l9 |0 m
如果我们再去掉一口,又返回第一种情况了。
# o3 b- b/ p# M6 `所以每一条大路,; E$ l: c( Y& f* s% w* `
按2珠路排列,有2种不同的路数。
! L. P/ u* t7 x6 I再举一个列子:* A( `5 Y! P. N7 L. s: U) v, o' z
大路:122122122122122122。。。* ^( Z! p: o1 B8 g" o0 {
按三珠路排列:
" |: ]8 D# X' S) t7 Z# S3 {) z122,122,122,122,122,122。。。# O# l+ ^! _ y2 [4 s3 b7 H
去掉第一口,变成:3 w2 h$ a& N! G2 |' H
221,221,221,221,221,; X& u$ c$ X' v. A K& N) I
去掉前2口,变成:
* b% U' T3 n( C: s212,212,212,212,212,
0 A4 D5 n; q& ~& J, T5 u/ R, F去掉3口,又返回122,122,122,了
% B- O+ E/ h& g& a# r所以每一条大路,
4 t! @4 [5 ]. C. E* z2 V. F按3珠路排列,有3种不同的路数。
6 ~; A" H& H9 W. y8 d, ^( C同理:按N珠路排列,有N种不同的路数。( U, T9 j3 I3 X7 ], n& H* p
我提出这个的意义在于:6 W, @% `/ ]2 a* L
字串8
. r" Z6 [3 c2 q0 i. p, `2 C# @4 S4 m- B; N# c& J! {! ]) W6 g( ~
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
9 {# W4 t2 Y3 o _* O+ j9 P0 m2、为三多理论提供了下注的多面性奠定基础。
1 C$ ]) R- E8 f! E1 \- a4 F3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.$ E3 \( [& y6 a) g4 m- [- j2 Z
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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