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[打法交流]
分享3d杀尾秘籍 助您轻松预测和值(四)(转)
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分享3d杀尾秘籍 助您轻松预测和值(四)1 @2 \0 k: B j T1 ?
(十八)同尾反杀排除和尾5 X4 T& Y7 A7 O5 y
选和值尾,我们找它上一期跟它相同尾的下一期是什么,那么我们就可以排除什么。同尾反杀这个概率还是很高的,它具体就是说,我们从下往上找,不管隔多远,只要找离它最近的相同的尾,找着相同的以后,相同的尾下面那期开的是什么尾的和值点,通常下一期我们都是可以排除的。这个方法的概率很高,同样,我们可以把这个方法也用在就是百、十、个位分位的杀号上。, @2 l5 D3 F$ d& I: I" x" y
(十九)用大号排除和尾, ~+ B, h0 W- o
最大数指的就是指在0到9十个自然数当中,最大的数是9,我们用9减去上一期奖号的和值尾,那么得出的数就是下一期我们可以排除的和值尾。5 B h8 g/ z: K7 F
(二十)跨度排除和尾
% I `" r, A X这个方法是这样的,例如某期奖号是924,那么它的跨度是7,也就是说下一期可以排除尾7的和值。尾7的和值包括包括7、17以及27,也就是说这三个点位所包含的全部的开奖号码,我们都是可以排除的。1 [' {+ u; V$ Z8 f O: Y
(二十一)平方和排除和尾' u/ \( x/ g" @# Q/ ~6 h) o
我们把奖号的百位跟百位相乘,得到一个数,十位和十位相乘又可以得到一个数,个位和个位相乘也同样的可以得到一个数,我们把百位的数字平方运算,和十位平方以及个位平方,把这三个数相加起来,我们取它的尾,这个尾的数就是下一期可以排除的和值尾。
) S; m! x+ a9 n(二十二)三期和尾差排除和尾9 o _) b" ~; {
所谓三期和值尾的差,就是我们用两期的和值把它相加起来的和,减去第三期和值得出来的这个差,就是下一期和尾不出的和尾(大减小)。7 X" x- b' P( B s1 ^/ \
(二十三)奖号百位排除和尾3 G1 K* \' J* X* N1 F9 T
用上期奖号的百位排除下期和值尾的方法,而这个和值尾,它通常代表是两个或三个的和值。例如,某期奖号开出的是924,那么百位的号是9,也就是说下期应该没有9的尾的和值。& e, l p# A2 }" |
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