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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。3 j9 ]4 w; m( `$ m2 \" q( d. S# K
* g3 }3 p: k! ^ l8 c& S! |
假设大路开这样的路:
+ w" E" k: ?4 X; E( z5 k0 e+ P7 G8 y
12121212121212121212121212121212。8 L$ E v% Q0 {# N; O
- T7 l# y+ V; r! z1 I 按2珠路,就是BPBPBPBPBP。8 d1 m1 r0 J4 X& w: a0 ]2 _
0 x" s2 ~2 S. b: [: D+ f
如果我们去掉第一口,就会出现完全相反的结果:) t! X1 p! S7 y+ t
/ }$ M6 J* r- E: g) M# X' r
21212121212121212121212121212121。# o" m) j$ v8 z, c H3 M; x9 v
( O e. n+ t; \7 G7 i8 K
变成了PBPBPBPBPB。
2 W" | S8 z9 f% F
q8 _# d) n# J5 H' o& { z; \ 如果我们再去掉一口,又返回第一种情况了。; `6 R) }, }" f6 N+ ]
# d$ Z7 k) c' f9 ` 所以每一条大路,按2珠路排列,有2种不同的路数。/ b0 B. N. L# [$ G
+ Z0 f6 _' e/ K; R# j 再举一个列子:( G [5 k: ]; c# b! _
4 t/ ^: P7 K$ n" F: G& D6 T) {% D 大路:122122122122122122。5 n" o" E8 u k1 S; k8 v
) {: s, o* w# _) a8 D; d
按三珠路排列:
( j r* w6 I& P6 F, w9 }2 I! C W
$ U" M2 g7 f& q& `4 w 122,122,122,122,122,122。
1 m5 z. v( o w1 H3 V" k, j1 Y, p0 n% W+ c; C* W I( X
去掉第一口,变成:
3 L9 h* \! p6 |$ t- I0 I
* y+ A5 t% k; s8 a9 V 221,221,221,221,221,去掉前2口,变成:# k( d# A2 {+ Q0 v- ], C
8 f. W, o+ u M5 D R- ~: A 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。. E8 A# _, m! F Y& c" Y
" I2 y9 U3 ~6 E% j8 g H 同理:按N珠路排列,有N种不同的路数。
+ y; a& U( b- R0 z, m1 B' k( `- ?# u- e+ ?5 d7 H
我提出这个的意义在于:
- X- c! q8 g/ _0 V4 c/ c/ w: i/ A) H+ ?6 c
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
0 m1 V1 Y* }. S: S/ C( _
& m+ n! S/ M0 ?& n I7 F 2、为三多理论提供了下注的多面性奠定基础。
; D8 J+ d) v5 r1 I5 W+ M
% g; J$ K1 `! T 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
! x6 Q3 e5 F+ t: A8 F0 x5 X5 g9 {: c/ P' K
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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