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[打法交流] 近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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1#
百家乐蒙特卡洛战术,需要纸和笔。但是不很难。+ M( b" @+ W9 \

; A4 v, {4 G; ~* y6 d# [) F. v" r(1) 首先写「 1 2 3 」的数列。+ p, j+ v6 J. x9 a: |4 w
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(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。, a6 v7 @7 T) c
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(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。. C& ?9 i5 e+ p% U0 z

% V& s9 k; f% J6 Q; N(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。- V$ r( H% @8 J0 I. x0 V/ c
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(5) 如果数列所有的数字都消了就代表结束。  u7 v  v, s- ~, O7 @" t, t

) r3 P$ S$ Y; @- f2 r4 F, t(6) 想继续的话,回到 (1) 。
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1 A- w/ \3 P8 ]0 r) s, \! ~蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。$ i3 B4 X; g& i

8 E! r* T4 J/ O( A( l, l二合一战术8 `+ F$ ^: g' N/ ?0 x: ?. N7 M

: L! {+ j/ B: z6 e" n7 o8 l) s这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。# ^2 q* S' q6 i! n/ _$ b& v7 x/ o
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譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。
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反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?
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儘管结果是 2 胜 4 败,共计收支是一加一减等于零。
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4 @! Q- z* Q0 _) W5 l5 o4 S这方法我试了不咋地,你们可能可以?, ?7 _8 u  J1 W* j' d
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2#
百家乐玩家可以来了解一下哦
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听着就复杂,谁研究出来的
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4#
这个战术也是来看看了解下的了啊
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主题回复处广告图案-天策传媒
我不相信什么战术,我只相信自己的运气。
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6#
看到第三条时我就看不懂了啊
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战术也是要看有没有用的呀
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看来要认真学习了,学好了就有饭吃
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9#
战术方面已经好久没有碰过了啦
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那也是要好好关注这方面的了
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11#
这战术也不是每个人都能用得上的吧
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这个战术我以前也是听说过的
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其实只要懂大数法则就不会信这东东
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14#
这个真的要仔细来研究下哦
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