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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。& ~" w" r" A+ X) g p, b
/ R% j2 y" S1 s( A6 p( X& c1 g 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)
3 S) V& c" ]% L7 X1 r, s- U3 Y* Y5 e
( P$ ^! I! m9 O6 k$ L4 p 第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
$ j3 i7 {9 q% Q7 f: K+ x
6 T' k+ ?6 j* ^. U4 f 第二行:O X X O O OX O X (第二行开始出现洞)
9 M7 P% F& t- R* q; v$ D- _! y$ ?4 z, H
第三行:O X O X X1 |' a( x) ?$ A
- O. k+ ?# S# X7 ]2 E4 n
第四行:O X X
% ]% H/ K8 K. B( }' l3 R# Y1 `! ~) ~( V
第五行: X9 f; k1 z2 B/ ], z X# t
. H5 ~; [) q, P8 J 那么新写出来的大路是怎么样的呢?3 j2 ~! q* k8 u, D1 w& T7 F J
: U9 D- M# N- k 记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。
, @* b% G8 g' a+ `0 I' P3 x/ I8 a: q- s( I9 [! F$ L
如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)# u4 t6 ^/ w+ g8 ~- r! z
4 D) l, s' m! X 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)
9 I( a1 F7 ]7 q; n+ \2 a' g r7 Z ^0 h
第二行:OOXXXOOX XXXXX (第二行也是全满的)) K$ a- E, A9 S: C
4 A/ F, {2 [+ w0 ~- V5 G 第三行:OX OX XO XOOX (第三行才出现洞)
- ]9 X1 b& _% J. @: Y8 M
: R6 ]! O$ w8 `1 z3 N; W 第四行:O XO O XXX 8 v8 k# G4 `7 t y8 Y) ]' T
7 x1 u/ ^. O3 I8 R$ G `
第五行: O
2 A8 V" @2 s3 A7 R- ~2 j
/ ~) }; T( [# p( s) L# D* H' V( a 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。
) i: M! z3 ~. m! g" K2 [$ Q3 G- H+ m2 Z3 p3 s0 T: z3 _. g% C% p E
大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。# Q% M- s0 R9 J8 W6 j. Z: ]
1 x; J! W- @2 z& _2 P
通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。! V# S/ I$ ~, j7 T
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