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[打法交流] 德州扑克手牌组合有多少种?(转载)
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起手牌组合3 {/ U# y; I6 A& g/ P
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德州扑克中可能的手牌组合数有C254=(54*53)/(2*1)=1326种特定的对子牌有C24=(4*3)/(2*1)=6种组合2 v: b2 ^) n! i" |7 Q
特定的非对子牌有4*4=16种组合
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特定的同花非对子牌有4*1=4种组合
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AXs有13-1=12种组合
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KXs有13-2=11种组合+ \, `: G: ^# @' G: ?
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" P+ I+ p% t$ @思考:去牌效应的应用。
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4 _" ?' J6 s, d9 C% pHERO手上有一张A,那么对手AA的组合还有多少呢?/ ^# V0 S5 ~/ Y# e2 `/ N9 f
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答:有C23=(3*2)/(2*1)=3种,与你没有A时的情况相比少了一半。
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8 J7 F9 n8 A' A9 K( U0 }HERO手上有一张A,那么对手AK的组合还有多少呢?% h( T: s3 a+ P$ a! M/ @

) y% D) B' p* Y( D% ?% S  O+ j答:有3*4=12种,与你没有A时的情况相比少了1/4。
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& O9 ^* U8 M/ M0 H5 B# c* M# \手牌组合3 ?* b, r+ ]; N& q8 K' {
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成牌组合
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- d$ |' w, S2 K2 @FLOP没有公对时:5 J6 \9 P6 H! O, u  A8 j/ n; S

# ~% u$ R$ h- Y6 n# w7 t三条的组合有C23*C23=9种* o% j. D" c6 X  x; k# a& h0 p2 L

5 E. R- a! Q! \* m& u. G) y指定三条的组合有C23=3种: ]0 s& F4 n" l! Y
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两对的组合有C23*C23*C23=27种
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9 }1 a; P8 S9 {指定两对组合有C23*C23=9种
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TPTK的组合有3*4=12种
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4 ~" `) h* A# [3 Q/ nFlop有公对时:
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0 V/ N9 y! n+ Y明三条顶踢脚的组合有2*4=8种
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; C5 O3 P) I" @: w2 W- k, f葫芦的组合有C23+C13*C12=9种7 j3 w2 o1 Y. z
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听牌组合
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FLOP有两张同花时:
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; V+ p5 o7 T, K$ k对手理论上的同花组合有C211=55种0 }( B5 d) K  [# @

! V2 p6 V' D" B- [而当你手上有一张同花时,对手理论上的同花组合有C210=45种
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+ h* A9 |! y5 _在类似K34这样的FLOP时:: @3 t# n& E: H% @2 X
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两头顺组合(25、56)有2*4*4=32种
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卡顺组合有(A2、26、57)3*4*4=48种) {3 k: p8 g) U$ W' \; }

9 p) S$ ]5 M9 L) e在类似K56这样的FLOP时:
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2 R% a9 Z$ ?% b+ g4 R+ Y+ c, {1 C两头顺组合有(34、47、78)3*4*4=48种
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卡顺组合有(24、37、48、79)4*4*4=64种$ N6 K( }1 R. S0 D9 ^! j

6 ?3 f9 b8 J$ a- t# V2 Y$ R; y& j1 E8 ?思考:当你知道对手只玩同花连牌时,组合数会发生怎样的变化呢?(这个请大家自己做个计算吧~)) F. `+ W3 @$ J4 O; W, e! A
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参与人数 1贡献值 +3 收起 理由
avatar 天策-瑶娥 + 3 理论区转载发帖奖励

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avatar
看来老哥也是专门研究的
avatar
那么还是有在多少种的时候了
avatar
理论的这个也是要看一下了
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26#
还是可以看看这个牌型了
avatar
这是要在看懂的啊,是有多少种
avatar
学习理论再加上自己修正才能变得更不错!
avatar
我现在还是研究一下理论打法,谢谢你的分享,我也来收藏
avatar
楼主的理论打法,玩起上来确实能控制振幅
avatar
这个理论应该是大家实践的收获。
avatar
20#
理论全体问题不大,重点掌握的好了
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19#
具体的理论打法还得让老哥来解答啊
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18#
这个理论打法说起来是绝对有效果的,我也来收藏
avatar
理论看看一下,肯定都是不会吃亏的。
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16#
老哥的理论打法还是很好啊,来收藏下了解下了
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这样的理论打法是十分科学好有道理哦,我也来收藏
avatar
这样的理论还是需要多多看看一下。
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