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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
. W6 Y5 a3 u* Y- }$ |2 a
7 L9 I3 D& O) o3 W- r# u4 r- @ 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)
+ s( Z, c4 J# \8 o# T
; I, z" _/ K# |. |. U1 Q 第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
! {, `1 e- L/ E' ?
& r8 O, a1 U L& _/ i2 E 第二行:O X X O O OX O X (第二行开始出现洞); x4 a- x/ R1 i7 R. u2 E0 f
- t& m& J0 H) B8 ?3 v% S
第三行:O X O X X
' A4 ^% _) d, ]3 |8 c! O3 o8 O& O+ X+ p4 I; C; |* U Q
第四行:O X X& u/ `8 O- d9 G! F
3 ^2 c; F- l1 |+ h, Y
第五行: X- |( Q% O" v, E; t
6 k3 V; ^+ ]' q ]
那么新写出来的大路是怎么样的呢?
* M2 ?5 C% {* r2 S- y+ V) _$ n8 v6 i7 U
记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。1 q: A! H: j( K6 ^- t( T& g
2 x& o$ ]$ J7 r2 R2 [3 ? 如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)( Q9 |, R- X/ K& H. E t
* @2 h. X6 P) y; e" [ 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)
* J) Z! }( _) r
- s# \) [) D$ p7 b# X' `5 w" C 第二行:OOXXXOOX XXXXX (第二行也是全满的)3 e3 e g* N. d1 B2 J, ~
4 I q2 n3 Z8 P! U% Z
第三行:OX OX XO XOOX (第三行才出现洞)8 b1 L$ S+ }! U1 F5 Z) J3 r2 K
/ ~. F( j& K5 x: K, o 第四行:O XO O XXX
# s3 J; }! x4 w! l W
- z/ o2 Y) p: `2 s 第五行: O. F9 Y2 g. D( N0 s3 |1 p) b4 c/ O7 t
8 q+ b5 ?0 B5 Y 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。
: |, X' ?+ o1 \* V
3 e5 D; t4 b3 B _' l% y$ v 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。* O& A: G# y0 A7 {& P
+ b0 G" C" M6 Z& a( O8 P' v
通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。8 f, R8 x5 |4 {% d5 V$ N P% m) j! I
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