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“四二法则”是一种估算概率的方法,让你能快速计算你想要的牌出现的概率。1 E9 t0 h$ {& h
) c; x0 ]' w! I* F$ T/ C7 M比如:桌子上的牌是A-6-7-Q,而你的手牌是8-9。你想要再来一张5或者10来凑成顺子,但你只剩最后一轮机会。
: C( B, x) f8 B0 {4 ~, H+ l I+ N& c& _. m4 l- M1 m0 i. g" p
严格来计算德扑概率应该这样:# [; v/ s5 R- n2 A( K! B# k0 C3 J0 {
" S) f+ ]# l' q/ a% R一副牌52张,去掉翻牌3张,转牌1张,手牌2张,剩下52-3-2-1=46张;
' j/ L, ~4 S4 v2 }
" @! d; U) u4 n/ m i' Q N你想要的牌是4张5和4张10,共4+4=8张。$ l6 z) j) S+ ]! z! `9 |
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那么此时,你在河牌中顺子的概率为:8/46=0.1739,即17%。
' j. D$ L7 C5 L5 z) n* X. ]/ d: J, ]5 W E+ Q% t' }. r* [4 M
你可能觉得这样计算会比较麻烦,于是就有了四二法则,即:你想要的牌有4+4=8张,
- f! G. v0 Q( F$ K
( j( p5 D0 l D+ |. ?只剩最后一轮机会,所以让8*2=16,即你有约16%的机会中顺子,与上述17%基本近似。0 X0 A" O7 M$ p6 U+ Y3 W% T f; G
1 ^, s) R5 `; Y0 f
这是四二法则中的“二”。
/ E9 M- X- ?; [4 i6 [( ]/ Q2 P" ]' l' P( u$ D2 H& e& z2 K# X
当然,如果你还有两轮机会的话,即河牌圈与转牌圈,情况是这样的。
0 |7 R$ q2 O' x% F$ v5 F5 v$ {; |1 m% c. G" Y0 p
比如桌子上翻牌为A-6-7,你的手牌依旧是8,9。
. ~$ `$ B7 H1 N
4 d8 T( o) l" I不一样的是,你有两轮机会来等5或者10,共8张想要的牌2 V$ C; y% b' S. L7 c
! ]- V4 U* |+ P0 @8 L2 ]6 D那么两轮内你中顺子的概率为:" x# y$ S* Q* e+ b: {& R2 t
) f5 [5 m: E5 R& X. d1-(47-8)/47*(46-8)/46=0.3145,即约为31%。( D2 D$ K3 u) G( F0 T" k
3 Y1 k8 J ]( N6 L那么利用四二法则,8*4=32,即你约有32%的机会中顺子,是不是跟理论值也很接近。5 s# i0 ]4 @+ M
: Z. \1 N+ [8 }* x4 a2 _7 ?( p
这就是四二法则中的“四”。7 ]+ ~ p ]5 _7 w
7 ]+ f+ X( N% A$ A6 }/ ~; ?: ^总之就是,先想好自己想要的牌的张数,然后,还有两轮机会就乘4,还有一轮机会就乘2,得到的就是你想要的牌接下来会出现的概率。接着,根据真人德扑圈的游戏玩家以及战况来决定接下来该怎么办。利用好四二法则,可以帮你快速估算概率。
/ j1 X. u; Z9 }
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我现在还是研究一下理论打法,感谢楼主的分享,我也来学习 |
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方法最后一段话觉得是实用的,但是在我面前就难以实现,毕竟运程太差了。 |
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